Imam sledeci kod:
$sql = MySql_Query("SELECT lt.translation, l.language_sign
FROM language l, language_translation lt
WHERE l.id = lt.id_language_translated
AND lt.id_language_source =
(SELECT id FROM language WHERE language_sign = '$language')") or die(mysql_error());
$result = MySql_Fetch_Array($sql);
$num_results = MySql_Num_Rows($result);
promenljiva $language nosi za ovaj primer predefinisanu vrednost "en". sql upit je testiran u bazi i vraca dva reda sa dva polja (language, sign):
english en
serbian sr
na echo $result je array
Javlja mi sledecu gresku:
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource
KAKO!!!!!
cheers
cony